Technology sharing

July 11th doctrina reprehendo-in, notitia structurae acervus

2024-07-12

한어Русский языкEnglishFrançaisIndonesianSanskrit日本語DeutschPortuguêsΕλληνικάespañolItalianoSuomalainenLatina

Salve omnes, propositum huius blogi est referre studiorum peractionem in aestivis vacationibus. In columna postea constituetur Post aliquot blogos cognatos circa exsequendam structuram datam et nonnullas quaestiones pro studio et usu personali. Etiam spero me multum posse sustinere.

1. Likou 115, minimus acervus

- LeetCode

Simpliciter utar ordine ad simulando acervum, sed hic studeo servare molestiam et celeritas currens non est valde alta, et multum locus est ad ipsum.

  1. class MinStack {
  2. int[] el;
  3. int numsize;
  4. public MinStack() {
  5. el = new int[10000];
  6. int numsize = 0;
  7. }
  8. // private void grow(){
  9. // this.el=Arrays.copyof(el,2*el.lenth);
  10. // }
  11. public void push(int val) {
  12. // if (el.lenth == numsize) {
  13. // grow();
  14. // }
  15. el[numsize] = val;
  16. numsize++;
  17. }
  18. public int pop() {
  19. if (empty())
  20. return -1;
  21. return el[--numsize];
  22. }
  23. public int top() {
  24. return el[numsize - 1];
  25. }
  26. private boolean empty() {
  27. return numsize == 0;
  28. }
  29. public int getMin() {
  30. int num = el[0];
  31. for (int i = 0; i < numsize; i++) {
  32. if (el[i] < num)
  33. num = el[i];
  34. }
  35. return num;
  36. }
  37. }
  38. /**
  39. * Your MinStack object will be instantiated and called as such:
  40. * MinStack obj = new MinStack();
  41. * obj.push(val);
  42. * obj.pop();
  43. * int param_3 = obj.top();
  44. * int param_4 = obj.getMin();
  45. */

2. Yang Hui triangulum

- LeetCode

Analysis: Ut sequenti tabula utamur, quam antea didicimus, sequenti tabula utimur ad solvendam hanc quaestionemDuo dimensiva ordinata tabula sequenti simulata simpliciter elementa per subscripta accedere non possunt.

  1. class Solution {
  2. public List<List<Integer>> generate(int numRows) {
  3. List<List<Integer>> ret=new ArrayList<>();
  4. List<Integer> list=new ArrayList<>();
  5. list.add(1);
  6. ret.add(list);
  7. for(int i=1;i<numRows;i++){
  8. List<Integer> row=new ArrayList<>();
  9. row.add(1);
  10. List<Integer> a= ret.get(i-1);
  11. for (int j = 1; j < i; j++) {
  12. int val1=a.get(j);
  13. int val2=a.get(j-1);
  14. row.add(val1+val2);
  15. }
  16. row.add(1);
  17. ret.add(row);
  18. }
  19. return ret;
  20. }
  21. }

Tres, press 150, aestimare econtrario expressio Polonica

Nota: expressio Poloniae est dictio quae per computers intelligi potest

- LeetCode

Idea: Percurre aciem, primo determina an chorda sit numerus;Si numerus est, in numerum convertitur et in acervum impellitur. Alioquin duae operandae eximuntur, et unum post "+", "*" vel "/" eximitur post. operator adhibetur.quod reliquum est in ACERVUS est extremum responsum

  1. class Solution {
  2. public int evalRPN(String[] tokens) {
  3. Stack<Integer> st = new Stack();
  4. for (int i = 0; i < tokens.length; i++) {
  5. String str = tokens[i];
  6. if (o(str) == false) {
  7. int val = Integer.parseInt(str);
  8. st.push(val);
  9. } else {
  10. int val1 = st.pop();
  11. int val2 = st.pop();
  12. switch (str) {
  13. case "+":
  14. st.push(val2+val1);
  15. break;
  16. case "-":
  17. st.push(val2-val1);
  18. break;
  19. case "*":
  20. st.push(val2*val1);
  21. break;
  22. case "/":
  23. st.push(val2/val1);
  24. break;
  25. }
  26. }
  27. }
  28. return st.peek();
  29. }
  30. private boolean o (String s){
  31. if (s.equals("+") || s.equals("-") || s.equals("*") || s.equals("/")) {
  32. return true;
  33. }
  34. return false;
  35. }
  36. }

Id est huius blog, omnibus gratias