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Da tibi productum quod duabus sequentibus proprietatibus satisfacit;m x nInteger matrix:

• In integri in quovis ordine dispositi sunt ordine non stricte crescendo a sinistro ad dextrum.
• Primus integer in quovis ordine major est ultimo integer in versu superiore.

Da tibi integrumtarget,sitargetIn vulvam, reditrue;false 。

innuere;

• m == matrix.length
• n == matrix[i].length
• 1 <= m, n <= 100
• -104 <= matrix[i][j], target <= 104

Idea: Primum quaerere ordinem possibilem, si intus est in versu, tunc vera redde

class Solution(object):
    def searchMatrix(self, matrix, target):
        """
        :type matrix: List[List[int]]
        :type target: int
        :rtype: bool
        """
        # 思路：先查找可能所在的行，如果在行里边，那么就返回true
        m = len(matrix)
        n = len(matrix[0])
        for i in range(m):
            if target in matrix[i]: # 如果在这一行中
                return True
            if target > matrix[i][n-1]: # 如果大于这一行最后一个元素值，那么就下一行
                continue
        return False